289-14(17)y-51y^2=0

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Solution for 289-14(17)y-51y^2=0 equation:


Simplifying
289 + -14(17) * y + -51y2 = 0

Multiply -14 * 17
289 + -238y + -51y2 = 0

Solving
289 + -238y + -51y2 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '17'.
17(17 + -14y + -3y2) = 0

Factor a trinomial.
17((1 + -1y)(17 + 3y)) = 0

Ignore the factor 17.

Subproblem 1

Set the factor '(1 + -1y)' equal to zero and attempt to solve: Simplifying 1 + -1y = 0 Solving 1 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1y = 0 + -1 -1y = 0 + -1 Combine like terms: 0 + -1 = -1 -1y = -1 Divide each side by '-1'. y = 1 Simplifying y = 1

Subproblem 2

Set the factor '(17 + 3y)' equal to zero and attempt to solve: Simplifying 17 + 3y = 0 Solving 17 + 3y = 0 Move all terms containing y to the left, all other terms to the right. Add '-17' to each side of the equation. 17 + -17 + 3y = 0 + -17 Combine like terms: 17 + -17 = 0 0 + 3y = 0 + -17 3y = 0 + -17 Combine like terms: 0 + -17 = -17 3y = -17 Divide each side by '3'. y = -5.666666667 Simplifying y = -5.666666667

Solution

y = {1, -5.666666667}

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